<PRE><B>Question 1058050</B>
Our Ho is variance = 150 minutes and H1 is variance &gt; 150 minutes
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degrees of freedom(df) = sample size - 1 = 25 - 1 = 24
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Note that variance = (standard deviation)^2
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variance of the sample = 15^2 = 225
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H1 does not contain an =, therefore we use a one-tailed test
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Our test statistic is calculated
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c = ((25 - 1) * 225) / 150 = 36
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alpha(a) = 0.05
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we check the chi-square distribution table
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df of 24 and a = 0.05 gives us a probability value(p-value) of 0.0549
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since our p-value &gt; 0.05, there is no reason to reject our null hypothesis(Ho)
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