Question 13249
The points you need to find are (2, y) such that the distance from (2,y) to (-2, -1) is 5.  You are right to use the distance formula!!

{{{ sqrt( (2-(-2))^2 + (y-(-1))^2) = 5}}}

Square both sides of the equation:
{{{ (4)^2 + (y+1)^2 = 25 }}}
{{{ 16 + (y+1)^2 = 25 }}}
{{{ (y+1)^2 = 9}}}

{{{ y+1 = 3}}} or {{{y+1=-3}}}
y=3-1; or y = -3 -1
y = 2 or y = -4


The points are (2,2) and (2, -4).


Check:  Distance from (2,2) to (-2, -1) = {{{sqrt (4^2 + 3^2) = 5}}}
Distance from (2,-4) to (-2, -1) = {{{sqrt (4^2 + 3^2) = 5}}}


R^2 at SCC