Question 1057937
{{{ x^2 - 4x + 3 = 0 }}}
You can complete the square
{{{ x^2 - 4x + (-4/2)^2 = -3 + (-4/2)^2 }}}
{{{ x^2 - 4x + 4 = -3 + 4 }}}
{{{ ( x - 2 )^2 = 1 }}}
Take the square root of both sides
{{{ x - 2 = 1 }}}
{{{ x = 3 }}}
and
{{{ x - 2 = -1 }}}
{{{ x = 1 }}}
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check answers:
{{{ ( x - 3 )*( x - 1 ) = x^2 - 4x + 3 }}}