Question 1057749

The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in standard form
<pre>Equation of a circle: {{{(x - h)^2 + (y - k)^2 = r^2}}}
(x, y) = (0, 3)
Midpoint of diameter, or center of circle (h, k) is on the y-axis, at the coordinate point:{{{matrix(1,3, "(0,", - 1/2, ")")}}}
{{{matrix(1,3, r = d/2, "=====>", r = 7/2)}}}
Equation of circle: {{{highlight_green(matrix(1,3, (x - 0)^2 + (y - (- 1/2))^2 = (7/2)^2, "======> ", x^2 + (y + 1/2)^2 = 49/4))}}}