Question 1057917
Let s be the speed of the truck going toward the delivery point. Then the return trip would be s+8. So:
450/s + 450/s+8=14.4
450(s+8)+450s=14.4s²+115.2s
14.4s²-784.8s-3600=0
144s²-7848s-36000=0 
Using the quadratic formula, we get two roots as a solution:-4.25495992697 and 58.754959927. Discarding the negative result, we get the outward trip speed as 58.755 kph. &#9786;&#9786;&#9786;&#9786;