Question 1057749
The midpoint of the line connecting (0,3) and (0,-4) is the center of the circle.
The distance from (0,3) to (0,-4) is the diameter.
{{{x[m]=(0+0)/2=0}}}
{{{y[m]=(3-4)/2=-1/2}}}
So then,
{{{D^2=(0-0)^2+(3-(-4))^2}}}
{{{D=7}}} so {{{R=7/2}}}
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{{{x^2+(y+1/2)^2=49/4}}}
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