Question 92336
graph x + 2y< 3 with a line under the sign
2x-3y < 6 with a line under the sign 
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Solve each for y as follows:
y <=(-1/2)x+(3/2)
y>=(2/3)x-2
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Graph the equalities:
{{{graph(400,300,-10,10,-10,10,(-1/2)x+(3/2),(2/3)x-2)}}}
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Pick a test point like (0,0)Substitute it into the inequalities
1st: 0 < (-1/2)*0+(3/2) ; true
2nd: 0 > (2/3)*0 -2 ; true
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Since that test point satisfies both of the inequlities that
area below the upper line and above the lower line is part
of the solution set----darken it.
The entire solution is the area you darkened and the boundaries
of that area.
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Cheers,
Stan H.