Question 1057847
Follow the formula for your standard form equation.  Zeros are easy to find because already in standard form.   {{{(x-3)^2+4=0}}}.  Try to solve this.  You should find two NONREAL complex roots.


You already know vertex is a minimum and is at  (3,4).  You already know symmetric around x=3.



{{{graph(400,400,-4,8,-4,8,(x-3)^2+4)}}}