Question 1057824
The hypotheses are:


Null: H0: µ = 100


Alternative: H1: µ > 100


This is a one-tailed, right-sided test with alpha = 0.05


The test statistic is:


z = (x-bar - µ) / (s/√n) = (106.8 - 100) / (22.7/√40) = 1.8946


Consulting a table of the normal distribution, or a statistical calculator, the p-value 
that corresponds to z = 1.8946 is p = 0.02907.


Since this p-value is less than the level of significance (0.05), the decision is to reject
the null hypothesis.


There is sufficient evidence at the 0.05 level of significance to support a claim that the
population mean is greater than 100.