Question 1057812
Let D represent the number of dimes, and let N represent the number of nickels.


Since Dan has 4 more quarters than dimes, the number of quarters can be represented as D + 4.


The total number of coins is:


(Number of quarters) + (Number of dimes) + (Number of nickels) = 21


(D + 4) + D + N = 21


2D + N + 4 = 21


2D + N = 17


The total value of the coins can be written as:


($0.25)(Number of quarters) + ($0.10)(Number of dimes) + ($0.05)(Number of nickels) = $3.35


(0.25)(D + 4) + (0.10)(D) + (0.05)(N) = 3.35


0.25D + 1 + 0.10D + 0.05N = 3.35


0.35D + 0.05N = 2.35


This gives a system of two equations:


2D + N = 17
0.35D + 0.05N = 2.35


This system can be solved simultaneously to get values for D and N. With the value of D, you can get the number of quarters by adding 4 to D.