<PRE><B>Question 92263</B>
In how many ways can a committee of six(6) members be selected from ten(10) students, namely, A, B, C, D, E, F, G, H, I,and  J so that 
a) at least one of the students A, F, and H will be included in the committee? 
b) not one of A, F, and H is included in the committee? 
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Prob(at least one of A,F,H is included) + Prob(none of A,F,H is included = 1
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Prob (none of A,F,H is included) = 7C6/10C6 = 7/210 = 1/30
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Prob (at least one of A,F,H is included) = 1 - 1/30 = 29/30
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Cheers,
Stan H.
</PRE>