Question 1057744
Original square:  {{{ x^2 = A }}}
Expanded square:  {{{ (x+2)^2 = A+24 }}}

From the top equation, we can substitute {{{x^2}}} for A in the bottom one:

                 {{{ (x+2)^2 = (x^2)+24 }}}
                 {{{ x^2+4x+4 = x^2 + 24 }}}
                 {{{  4x+4 = 24 }}}    (subtracted {{{x^2}}} from both sides
                 {{{  x+1 = 6 }}}     
            Ans:  {{{ x=5m }}}

Check:
             {{{ A=5^2 = 25 m^2 }}}
         and {{{ (5+2)^2 = 7^2 = 49 m^2}}} which is 24 more than 25