Question 1057700
There are two vowels in the first 8 letters of the alphabet (a and e). Since 
these two letters must be included in every word, we must select 3 additional
letters from the remaining 6 consonants to get a group of 5 letters.


There are {{{C(6, 3) = 6!/(3!(6 - 3)!) = 20}}} ways to do this, so there are 
20 different five letter groups.


For each group, the five letters can be arranged in 5! = 120 ways.


The total number of "words" is then:


(120 words per group)(20 groups) = <strong>2400 words</strong>