Question 1057373
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The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister. 
Find the age of the brother and sister.
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<pre>
Let B be the brother's present age. 
Then the sister's present age is 44-B.

In 5 years the brother will be (B+5) years old. 
while sister will be 44-B + 5.

We are given that

B+5 = 2(44-B+5).

Simplify and solve for B:

B + 5 = 88 - 2B + 10,

B + 2B = 88+10-5,

3B = 93,

B = {{{93/3}}} = 31.

<U>Answer</U>. The brother's present age is 31 year. The sister is 44-31 = 13 years old.
</pre>

There is a bunch of lessons on age word problems 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Age-problems-and-their-solutions.lesson>Age problems and their solutions</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Fresh-formulation-of-a-traditional-age-problem.lesson>A fresh formulation of a traditional age problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Really-intricate-age-word-problem.lesson>Really intricate age word problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/Selected-age-word-problems-from-the-archive.lesson>Selected age word problems from the archive</A>

in this site.


Read them and become an expert in solving age problems.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Age word problems</U>".