Question 1057188
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{{{ (1/2^n)+(3/2^3)+(5/2^n-3)-(82/2^n+1) }}} i have the answer which is {{{ 3/8 }}} but how do i get i only got 1 step ahead, 
and i don't mean the n i mean the the equation equals 3/8 but not the n, so how do i get the equation to 3/8 
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<pre>
{{{1/2^n}}} + {{{5/2^(n-3)}}} - {{{82/2^(n+1)}}} = {{{1/2^n}}} + {{{(5*8)/2^n}}} - {{{41/2^n}}} = {{{(1 + 40 -41)/2^n}}} = 0.
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