Question 92397
Let x=1st integer, y=2nd integer


Translation:

Equation 1:{{{x*y=32}}} "The product of two integers is 32"


Equation 2:{{{y=2x}}} "One integer is twice the other"


{{{x*highlight(2x)=32}}} plug in y=2x into equation 1


{{{2x^2=32}}} Multiply


{{{x^2=16}}} Divide both sides by 2


*[Tex \LARGE x=\pm4] Take the square root of both sides


So we get {{{x=4}}} or {{{x=-4}}}



Now plug in {{{x=4}}} to find y


{{{y=2(4)=8}}}


So when {{{x=4}}}, {{{y=8}}}




Now plug in {{{x=-4}}} to find y


{{{y=2(-4)=-8}}}


So when {{{x=4}}}, {{{y=-8}}}



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Answer:


So we have 2 possible pairs of numbers


The two numbers could be either

4 and 8

<b> or </b>

-4 and -8