<PRE><B>Question 1057242</B>
.
A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more 
than twice the number of quarters, how many of each type of coin are there?
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&lt;pre&gt;
From the condition, you have these two equations

10d + 25q = 255,   (1)
d = 2q + 3.        (2)

substitute expression (2) to the equation (1), replacing d. You will get

10(2q +3) + 25q = 255,   or

20q + 30 + 25q = 255,  or

45q = 255 - 30,

45q = 225.

q = {{{225/45}}} = 5

5 quarters and 2*5 + 3 = 13 dimes.
&lt;/pre&gt;

Sorry, it was MY mistake.


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