Question 1057210
Write an equation, in standard form,  of a line that is perpendicular to the line 2(x-3)=-y+5 has the same y-intercept as the line 3x-2y=-7.
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Find the slope and y-int of 2(x-3)=-y+5
2x-6 = -y+5
y = -2x + 11
Slope m = -2
The slope of lines perpendicular is the negative inverse, = +1/2
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3x-2y=-7
Find the y-int
Solve for y.
y = (3/2)x + 7/2
y-int, b = 7/2
y = mx + b
y = (1/2)x + 7/2
2y = x + 7
x - 2y = -7