<PRE><B>Question 1057194</B>
Let  n  be the smallest integer

Then  n+1 and n+2 represent the next two consecutive integers.

10n = 22+3(n+(n+1)+(n+2))    &quot;10 times the smallest is 22 more than 3 times the sum of integers&quot;
10n = 22+3(3n+3)
10n = 22+9n+9
    n = 31
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Ans:  The integers are 31, 32, and 33
—

Check:
  10 * 31 = 310
  22+3(31+32+33) = 310 (ok)
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