Question 13004
You would start off by bringing all the variables to one side and the constants to another:
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3a-8=(a/2)+2
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Becomes: 3a-(a/2)=10
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Now, we multiply each side by 2 so to get rid of the denominator in a/2:
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2(3a-(a/2))=2(10)
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Becomes: 6a-a=20 
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Becomes: 5a=20
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Divide each side by 5:
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a=4