Question 1056992
.
A long distance runner start at the beginning of a trail and runs at a rate of 6 mph.  Two hours later, a cyclist starts at the beginning 
of the trail and travels at a rate of 16 mph. What is the amount of time that the cyclist travels before overtaking the runner? 
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
{{{(2*6)/(16-6)}}} = {{{12/10}}} = {{{1}}} {{{2/10}}} hours = 2 hours 12 minutes.


2*6 in the numerator is the distance (in miles) the runner was ahead the cyclist at the moment cyclist started his move.

16 - 6 = 10 mph is their relative speed.
</pre>

For introductory lesson on Travel and Distance see

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>