<PRE><B>Question 1056885</B>
Solve for x

 8x^9=6x^6
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x = 0 is obvious.
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8x^9 = 6x^6
8x^3 = 6
x^3 = 6/8
x = {{{root(3,6)/2}}}
Is that sufficient?
Those 2 are the real roots.

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