Question 92350
{{{ 14x^2 - 20x + 6 }}}
Compare above equation  with standard quad equation {{{ax^2+bx+c}}}
we get
a = 14
b = -20
c = 6


Discriminant: {{{b2-4ac}}} = {{{20^ 2-4*14*6 = 64 }}}

Discriminant (64) is greater than zero. The equation has two solutions.
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

or
{{{x = (-(-20) +- sqrt( (-20)^2-4*14*6 ))/(2*14) }}} 

or

x1,2 = (20 ± 8) / 2*14
or

x1 = 28 / 28 = 1
x2 = 12 / 28 = 3/7

or

x1,2 = 1, 0.428

Equation factored:

14(x-1)(x-0.428)