Question 92373
{{{-3x^2-10+8 }}}
Compare the above equation with standard quadratic equation {{{ax^2+bx+c}}}
we get
a = -3
b = -10
c = 8


Discriminant: {{{b^2-4ac}}} = {{{ 10^2+4*(-3)*8 = 196}}} 

Discriminant (196) is greater than zero. The equation has two solutions.

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
or
{{{x = (-(-10) +- sqrt( (-10)^2-4*(-3)*(8) ))/(2*(-3)) }}}
or

x1,2 = (10 ± 14) / 2*-3
or

x1 = 24 / -6 = -4
x2 = -4 / -6 = -2/-3=2/3=0.666

or

x1,2 = -4, 0.666 


Equation factored:

-3(x+4)(x-0.666)