Question 1056852
<pre><b><font size = 4>
Get some graph paper and draw an x and a y axis:

Start at the point (2,-4):

{{{drawing(300,300,-2,9,-7,4, grid(1),circle(2,-4,.1),circle(2,-4,.15),
locate(2,-4,"(2,-4)")  )}}}

The numerator of the slope 2/3 is 2, so from that point
draw a line straight up which is 2 units long. That's the
red line below:

{{{drawing(300,300,-2,9,-7,4, grid(1),circle(2,-4,.1),circle(2,-4,.15),
locate(2,-4,"(2,-4)"),red(line(2,-4,2,-2),line(2.01,-4,2.01,-2),
line(2.08,-4,2.08,-2),line(1.96,-4,1.96,-2)

)  )}}}

The denominator of the slope 2/3 is 3, so from the end of 
the red line, draw a line to the right which is 3 units long. 
That's the green line below:

{{{drawing(300,300,-2,9,-7,4, grid(1),circle(2,-4,.1),circle(2,-4,.15),
locate(2,-4,"(2,-4)"),red(line(2,-4,2,-2),line(2.01,-4,2.01,-2),
line(2.08,-4,2.08,-2),line(1.96,-4,1.96,-2)),green(line(2,-2,5,-2),
line(1.96,-2.08,5,-2.08),line(1.96,-1.92,5,-2))


  )}}}

Now get a straight edge and draw a line through (2,-4) and the 
end of the green line.

{{{drawing(300,300,-2,9,-7,4, grid(1),circle(2,-4,.1),circle(2,-4,.15),
locate(2,-4,"(2,-4)"),red(line(2,-4,2,-2),line(2.01,-4,2.01,-2),
line(2.08,-4,2.08,-2),line(1.96,-4,1.96,-2)),green(line(2,-2,5,-2),
line(1.96,-2.08,5,-2.08),line(1.96,-1.92,5,-2)), line(-7,-10,11,2)


  )}}} 

That's the line!

[In other problems when the slope is a negative number, the first
line goes straight down the numerator instead of straight up, but
the second line still goes to the right.]

Edwin</b></pre></font>