Question 1056795
{{{f(x)+g(x)=(x-6)/(x-1)+1/(x-1)}}}
Obviously domain must exclude +1.
All other real numbers are the domain.


{{{f(x)g(x)=((x-6)/(x-1))(x-1)}}}
Same thing here.  The function is NOT the result of cancleling the factor of 1.  The product is still undefined at x=1.  That is the way the product is written, formed.