Question 1056568
1.{{{(A+B+C+D+E)/5=77}}}
2.{{{(A+B+C+D)/4=74}}}
From 1,
{{{A+B+C+D+E=385}}}
and from 2,
{{{A+B+C+D=296}}}
Subtracting,
{{{(A+B+C+D+E)+(A+B+C+D)=385-296}}}
{{{E=89}}}
.
.
.
{{{(A+B+C+D+E+F)/6=80}}}
{{{A+B+D+C+D+E+F=480}}}
{{{385+F=480}}}
{{{F=95}}}
Yes, the student needs a 95.