Question 1056675
What do you want with this?  You categorized your posting in Inverse Operations for addition and multiplication, or reciprocals.


A guess about the expression you really have is that, {{{y=(-4x+3)/(8x-1)}}}.  If you want the function inverse, then a quick way can be exchange x and y and solve for y.


{{{(-4y+3)/(8y-1)=x}}}


{{{-4y+3=8xy-x}}}


{{{-4y-8xy+3=-x}}}


{{{4y+8xy-3=x}}}


{{{y(4+8x)=x+3}}}


{{{y=(x+3)/(8x+4)}}}