Question 1056593

Find the numerator: (3m+6)/(m^2-m)=(?)/(m^3-5m^2+4m)

I have a problem asking me to find the numerator of the second rational expression. I am not exactly sure how to go about doing this. I would appreciate a detailed step by step description on how to solve this so I can learn from it.

Thank you!
<pre>{{{matrix(1,3, (3m + 6)/(m^2 - m), "=", "?"/(m^3 - 5m^2 + 4m))}}} =====> {{{matrix(1,3, (3(m + 2))/m(m - 1), "=", "?"/(m(m^2 - 5m + 4)))}}} =====> {{{matrix(1,3, (3(m + 2))/m(m - 1), "=", "?"/(m(m - 4)(m - 1)))}}} =====> {{{matrix(1,3, (3(m + 2)(m - 4))/(m(m - 1)(m - 4)), "=", "?"/(m(m - 4)(m - 1)))}}} =====> {{{highlight_green(matrix(1,3, (3(m^2 - 2m - 8))/(m(m - 1)(m - 4)), "=", highlight(3(m^2 - 2m - 8))/(m(m - 4)(m - 1))))}}}