Question 1056592
I'm trying to get this expression down to a single logarithm.
1/4 log (x-2) - log(x) + log 8

log (x-2)^1/4 - (log x - log 8)
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You were ok, but then what happened to the 1/4?
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log x-2- log x- 8 Is any of the right so far?

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1/4 log (x-2) - log(x) + log 8
= {{{log(root(4,(x-2))) - log(x) + log(8)}}}
= {{{log(8*root(4,(x-2))) - log(x)}}}
= {{{log(8*root(4,(x-2))/x)}}}
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PS  x > 2