Question 1056593
Find the numerator: (3m+6)/(m^2-m)=(?)/(m^3-5m^2+4m) 
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Factor where you can::
[3(m+2)/m(m-1)] = ?/[m(m^2 - 5m + 4)]
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[3(m+2)/m(m-1)] = ?/[m(m-4)(m-1)]
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[3(m+2)] = ?/(m-4)
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? = 3(m+2)(m-4)
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Cheers,
Stan H.
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