Question 92183
(A) {{{sqrt(3)(sqrt (6) - 2sqrt(3))}}}
Multiply what is inside the brackets by {{{sqrt(3)}}}, you have:
{{{sqrt(18) - 2(3)}}}; sqrt(3)*sqrt(3) = 3
:
same as
{{{sqrt(2*9) - 6}}};
:
extract the sqrt of 9
{{{3sqrt(2) - 6}}}   
:
:
(B) {{{(sqrt(18)- sqrt(3))/(sqrt(6))}}}* {{{sqrt(6)/sqrt(6)}}} = {{{(sqrt(108)- sqrt(18))/6)}}} = {{{(sqrt(36*3)- sqrt(2*9))/6}}} = {{{(6sqrt(3)- 3sqrt(2))/6)}}}
:
Reduce this fraction divide each term by 3:
{{{(2sqrt(3)- sqrt(2))/2)}}}
:
How about this? Make sense to you?