Question 1056473
Something is wrong with what you have stated above.  

Either

{{{y=x^2/10-6x/5+2/5}}}

is not the answer or else the vertex is not (6,-2)

The vertex of any parabola is a point on the parabola
and therefore must satisfy the equation of the parabola.

However, (6,-2) DOES NOT satisfy the equation!

{{{y=x^2/10-6x/5+2/5}}}

Proof that it doesn't:

{{{(-2)=(6)^2/10-6(6)/5+2/5}}}

{{{-2=36/10-36/5+2/5}}}

{{{-2=18/5-36/5+2/5}}}

{{{-2=-16/5}}}

That is clearly false.

The parabola that you say is the answer

has vertex (6,-16/5),

focus (6,-7/10),

and directrix y = -57/10.

------------------------

The parabola that has focus at (6,2), vertex at (6,-2) 
the directrix line at y=-6, has this equation:

{{{y = x^2/16-3x/4+1/4}}}

I would have shown you how to get that, but since the
answer you said is correct is incorrect, I thought
I'd better wait until I was sure you had everything
correct before doing it.  If you want to discuss it
with me, you may do so in the thank-you note form
below and I'll get back to you by email.

Edwin</pre>