Question 1056313
sin(A-B)/cos(A+B) = 1/3[tan(A-B)]
<pre><b>
There is something wrong with this problem.
Here's why I say this:

It is certainly true if A = B = 0

sin(0-0)/cos(0+0) = 1/3[tan(0-0)] 

0/1 = 1/3[0]

0 = 0

Yet tanA*tanB = 0*0 = 0 , not -1/2.

Edwin</pre></b>