Question 1056163
sin(y+π/6)cos(y+π/6)= cos^2(y+π/6)
sin(y+π/6)cos(y+π/6)/cos^2(y+π/6)=1
sin(y+π/6)/cos(y+π/6)=1
tan(y+π/6)=1
tan(y+π/6)=tanπ/4
(y+π/6)=π/4
y=π/4-π/6
y=π/12