<PRE><B>Question 1056161</B>
1.Use factoring and the zero product property to solve the question. 
2x^3-6x^2-8x+24=0
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2x^2(x-3)-8(x-3) = 0
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(x-3)(2)(x^2-4) = 0
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2(x-2)(x+2)(x-3) = 0
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x = 2 or x = -2 or x = 3
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2.Factor this expression over the complex numbers.

x^4+5x^2+4 
(x^2+4)(x^2+1) = 0
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Express your answer as the product of binomials.
(x-2i)(x+2i)(x-i)(x+i) = 0
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Cheers,
Stan H.
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