Question 1056046
Q(t) = Q(0)e^(-kt)
Q(t) = 10000e^(-.12t)
Q(7) = 10000e^(-.12*7)
|(c) How long does it take to reduce the number of cases to 1000? 
1000/10000 = e^(-.12*t)
ln(.1) = -.12t
ln(.10)/.12 = t