Question 1056146
The area of the rectangular field, A = l*w
The perimeter of the fenced in area is 2(l+w) = 500 m
Express w in terms of l: w = 250 - l
Therefore A = l(250-l)
The largest area will be obtained where dA/dl = 0 = 250 - 2l
Solve for l:
l = 250/2 = 125 m
w = 250 - 125 = 125 m
So length and width are both 125 m, i.e. a square