Question 1056142
{{{f(x)=a(x-3)(x-4i)(x+4i)=a(x-3)(x^2+16)}}}
{{{f(1)=a(1-3)(1^2+16)=-34}}}
{{{a(-2)(17)=-34}}}
{{{-34a=-34}}}
{{{a=1}}}
So,
{{{f(x)=(x-3)(x^2+16)}}}