Question 1056059
David has a total of $4.25. He has twice as many dimes as nickels. The number of quarters that he has is three less than the number of nickles. how many of each coin does he have?
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Value Eq:: 5n + 10d + 25q = 425 cents
Quantity:: q = n-3
Quantity:: d = 2n
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Divide through the 1st by 5
Substitute for "q" and for "d"
Solve for "n"::
n + 2d + 5q = 85
n + 2(2n) + 5(n-3) = 85
10n - 15 = 85
10n = 100
n = 10 (# of nickels)
d = 2n = 20 (# of dimes)
q = n-3 = 7 (# of quarters)
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Cheers,
Stan H.
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