Question 1056039

Solve for x: 9^(2x-1)=(1/3)^x
<pre>{{{9^(2x - 1) = (1/3)x}}}
{{{(3^2)^(2x - 1) = (3^-1)^x}}} ----- Converting {{{matrix(1,7, 9, to, 3^2, and, 1/3, to, 3^- 1)}}}
{{{3^(2(2x - 1)) = 3^(- x)}}}
{{{3^(4x - 2) = 3^(- x)}}}
4x – 2 = - x ------ Bases of equation are equal and so are the exponents
4x + x = 2
5x = 2
{{{highlight_green(x = 2/5)}}}