Question 1056039
Solve for x: 9^(2x-1)=(1/3)^x
----------
(2x-1)*log(9) = x*log(1/3)
2x*log(9) - log(9) = x*log(1/3)
2x*log(9) - x*log(1/3) = log(9)
x*log(81) - x*log(1/3) = log(9)
x*(log(81) - log(1/3)) = log(9)
x*log(243) = log(9)
x = log(9)/log(243) = 2log(3)/(5log(3))
x = 2/5