<PRE><B>Question 1056026</B>
 How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze?
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active + active = active
0.5x + 0.10*70 = 0.4(x+70)
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50x + 10*70 = 40x + 40*70
10x = 30*70
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x = 210 gallons (amt of 50% antifreeze needed)
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Cheers,
Stan H.
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