Question 1055939
The mean and the variance of the Poisson are the same, and 1 is very near the mean, so there should be a reasonably significant probability, although the variance/sd are both 1.  There will be a significant tail
P(1)=e(^-0.9)(0.9)^1/1!
That is 0.9*e^(-0.9)=0.3659