Question 1055931
.
find the perimeter of a trapezoid with 3 ft. in height and 7 ft. and 8 ft. in both {{{highlight(lateral)}}} sides. The area is 10 ft
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


My dear, the area can not be 10 ft.
The area is measured in square units.
So, I will assume that the area is 10 {{{ft^2}}}.


<pre>
1.  Having the area and the height, you can find the half of the sum of the bases.

    If the bases are "a" and "b", then {{{(a+b)/2}}} = {{{area/height}}} = {{{10/3}}} ft.


2.  Having the half of the sum of the bases, you can find the sum itself:

    a + b = {{{(2*10)/3)}}} = {{{20/3}}} ft.


3.  Finally, you will find the perimeter by adding the lateral side lengths 7 and 8 ft to {{{20/3}}} ft.


<U>Answer</U>. The perimeter is 7+8+{{{20/3}}} ft.
</pre>