Question 1055860
Let w be the width of the flag. Then the length would be 2w-3. So:
W (2w-3)=1710
2w^2-3w-1710=0
(2w+57)(w-30)=0
w=-57/2, 30
The width of the flag is 30 in.; the length is 57 in....😊😊😊😊