Question 1055760
So there are 3 even faces and 3 odd faces.
{{{P(odd)=3P(even)}}}
{{{3P(odd)+3P(even)=1}}}
{{{3(3P(even))+3P(even)=1}}}
{{{12*P(even)=1}}}
{{{P(even)=1/12}}}
{{{P(odd)=3/12=1/4}}}
So then,
{{{P=P(1)+P(2)+P(3)}}}
{{{P=P(odd)+P(even)+P(odd)}}}
{{{P=3/12+1/12+3/12}}}
{{{P=7/12}}}