Question 1055811
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Hi  
Need to know:
The vertex form of a Parabola opening up(a>0) or down(a<0), 
{{{y=a(x-h)^2 +k}}} where(h,k) is the vertex 
 {{{y=1(x-4)^2 -1 }}}
V(4, -1)
As to additional Point:  Plug x in to find y
x  y 
3  0
2  3
5  0
6  3
{{{drawing(300,300, -10, 10, -10, 10,  grid(1),
circle(4,-1,0.4),
circle(3,0,0.4),
circle(2,3,0.4),
circle(5,0,0.4),
circle(6,3,0.4),
graph( 300, 300,  -10, 10, -10, 10,0,(x-4)^2 -1))}}}