Question 1055753
Easiest to just use standard form equation  (x-h)^2+(y-k)^2=5^2, and you know that one point  (x,y)  is  (5,0).



{{{(5-h)^2+(0-k)^2=25}}}

{{{(5-h)^2+k^2=25}}}, and this is all you can do, because this is one equation with still two unknown variables.  There are infinite number of circles that will work.  Pick a convenient value for k.  OR, pick a convenient value for h.