Question 1055736
Using the point-slope form linear equation y-3=3(x+1),what is the slope of the given line,and what point does this line pass through,which is the basis of this equation?

Thank you  very much.
<pre>Point-slope form: {{{y - y[1] = m(x - x[1])}}}
Compare to:       y - 3 = 3(x + 1)
You should see that: {{{matrix(1,6, - y[1] = - 3, ",", m = 3, and, ",", - x[1] = 1)}}} 
Thus, {{{matrix(1,6, y = 3, ",", m = 3, ",", and, x = - 1)}}}
Slope = m = 3, and point this line passes through is: (x, y), or (- 1, 3)